(HELP ASAP PLEASE)Solve using any method and fill in the blanks.Lloyd's Bakery sold one customer 9 dozen chocolate cookies and 8 dozen oatmeal cookies for $110. The bakery also sold another customer 9 dozen chocolate cookies and 5 dozen oatmeal cookies for $89. How much do the cookies cost?A dozen chocolate cookies cost $___ and a dozen oatmeal cookies cost $___

Answer:A dozen chocolate cookies cost $6and a dozen oatmeal cookies cost $7Step-by-step explanation:Let's assume that cost of 1 dozen chocolate cookies = xLet's assume that cost of 1 dozen oatmeal cookies = ythen we get equations:9x+8y=110...(i),and 9x+5y=89...(ii)Solve equation (i) for x9x+8y=1109x=110-8y[tex]x=\frac{110-8y}{9}[/tex]...(iii)plug (iii) into (ii)9x+5y=89[tex]9\left(\frac{110-8y}{9}\right)+5y=89[/tex][tex]110-8y+5y=89[/tex][tex]9\left(\frac{110-8y}{9}\right)+5y=89[/tex][tex]110-3y=89[/tex][tex]-3y=89-110[/tex][tex]-3y=-21[/tex][tex]y=7[/tex]plug y=7 into (iii)[tex]x=\frac{110-8y}{9}=\frac{110-8(7)}{9}=6[/tex]So the final answer is given by:A dozen chocolate cookies cost $6and a dozen oatmeal cookies cost $7