A conductor possesses a positive charge of 3.2x 10-19 C. How many electron does it have in excess or deficit (e = 1.60 x 10-19C)
Accepted Solution
A:
The no of electrons it have in deficit=1.60
Given:
Charge possessed by a conductor = [tex]3.2 \times 10^{-19} C[/tex]Charge of an electron=[tex]1.6 \times 10^{-19} C[/tex]To find:
Amount of electrons in excess or deficit
Step by Step Explanation:
Solution;
Formula used for calculating electrons in excess or deficit is given as
Electrons in excess or deficit= Normal electron charge- Charge of the conductorAlso we know Charge of Conductor[tex]=3.2 \times 10^{-19} C[/tex] and Electron charge[tex]=1.6 \times 10^{-19} C[/tex] Substitute these values in the above equation we get
Electrons in excess or deficit=[tex]1.60 \times 10^{-19} \mathrm{C}-3.2 \times 10^{-19} \mathrm{C}[/tex]= -1.60
Result:
Hence, it has a deficit of 1.60 electrons.